0=9x^2-252x+1188

Solution for 0=9x^2-252x+1188 equation:

0=9x^2-252x+1188

We move all terms to the left:

0-(9x^2-252x+1188)=0

We add all the numbers together, and all the variables

-(9x^2-252x+1188)=0

We get rid of parentheses

-9x^2+252x-1188=0

a = -9; b = 252; c = -1188;
Δ = b2-4ac
Δ = 2522-4·(-9)·(-1188)
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(252)-144}{2*-9}=\frac{-396}{-18}
=+22
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(252)+144}{2*-9}=\frac{-108}{-18}
=+6
$